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TimWard70
Regular Contributor
Regular Contributor

I think this is summarised as adding a new option to the rank function "Minium_Sequential"

有两个或更多在哪里values tied at a particular rank the rank for the next value would be one lower than the preceding rank, rather than 2 lower as is currently the case with the "Minimum" option.

For example:

Value Rank

20 1

20 1

20 1

15 2

10 3

10 3

5 4