评论
02-03-202110:11 AM
02-03-202110:11 AM
I think this is summarised as adding a new option to the rank function "Minium_Sequential"
有两个或更多在哪里values tied at a particular rank the rank for the next value would be one lower than the preceding rank, rather than 2 lower as is currently the case with the "Minimum" option.
For example:
Value Rank
20 1
20 1
20 1
15 2
10 3
10 3
5 4